Q7 A diet for a sick person must contain at least 4000 units of vitamins, 50 units of minerals and 1400 calories. Two foods A and B are available at a cost of Rs.4/- and Rs. 3/- per unit respectively. If one unit of A contains 200 units of vitamins , 1 unit of mineral and 40 calories and one unit of food B contain 100 units of vitamins, 2 units of minerals and 40 calories, find by graphic method, what combination of foods be used to have least cost?
Ans: Minimize (Z) = 4×1+3×2
Subject to constraints
200×1+100×2≥4000, x1+2×2≥50, 40×1+40×2≤1400
Non Negative Restrictions x1, x2≥0
Z=110 x1=5, x2=30
